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2x^2=52-5x
We move all terms to the left:
2x^2-(52-5x)=0
We add all the numbers together, and all the variables
2x^2-(-5x+52)=0
We get rid of parentheses
2x^2+5x-52=0
a = 2; b = 5; c = -52;
Δ = b2-4ac
Δ = 52-4·2·(-52)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-21}{2*2}=\frac{-26}{4} =-6+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+21}{2*2}=\frac{16}{4} =4 $
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